Class name Subject Book title Chapter number Content Created at
Class VII Mathematics Ganita Prakash-II 6 CONSTRUCTIONS AND TILINGS 6.1 Geometric Constructions Eyes Do you recall the ‘Eyes’ construction we did in Grade 6? Of course, eyes can be drawn fr...
Class VII Mathematics Ganita Prakash-II 6 and below XY, always be the perpendicular bisector of XY, i.e., when XY is of any length, and the arcs are drawn using a radius of any length? This...
Class VII Mathematics Ganita Prakash-II 6 choose two other points C and D such A that CX = CY = DX = DY. An eye of a different shape can be drawn using these points. Will C and D lie on the...
Class VII Mathematics Ganita Prakash-II 6 and a compass. We will use only these two tools for all the other geometric constructions in this chapter, unless there is a need for drawing lines...
Class VII Mathematics Ganita Prakash-II 6 angle at point O. Find a segment of this line for which O is the midpoint. Extend the line on either side of O. Using a compass, mark two points X ...
Class VII Mathematics Ganita Prakash-II 6 need to construct a perpendicular bisector. Fix a small pole or peg vertically into the ground at each point X and Y. Take a sufficiently long rope...
Class VII Mathematics Ganita Prakash-II 6 X We will now develop a general method to bisect any angle. Consider an angle ∠XOY. O Y X We can bisect it if we can draw two congruent B triangles...
Class VII Mathematics Ganita Prakash-II 6 a given square? Repeating Units and Repeating Angles Construct the following figure. Fig. 6.6 In this figure, there is a single unit repeating itse...
Class VII Mathematics Ganita Prakash-II 6 to get parallel lines. How do we implement this idea using a ruler l and a compass? a Suppose there is a line m to which we need to draw a parallel...
Class VII Mathematics Ganita Prakash-II 6 and ∠BAD = ∠CDA. How would you construct these support lines? B C A D A D Construct equal angles at A and D. Mark B and C such that AB = CD. Use th...
Class VII Mathematics Ganita Prakash-II 6 regular hexagon has equal sides and angles, can we expect a figure like this? O Will all the triangles in the figure be equilateral E C triangles? ...
Class VII Mathematics Ganita Prakash-II 6 We can construct a regular hexagon more directly if we can construct a 120° angle using a ruler and a compass. How do we do it? This can be done if...
Class VII Mathematics Ganita Prakash-II 6 the following figure? How does this happen? Recreate this in your notebook. 3. Construct this figure. [Hint:Findtheanglesinthisfigure.] Try 4. Draw...
Class VII Mathematics Ganita Prakash-II 7 the unknown x on the LHS, we need to remove the factor 5. This can be done by dividing both sides by 5. 5x 11 Thus, 5 = 5  . So, x =5 . 170 Finding...
Class VII Mathematics Ganita Prakash-II 6 squares. 157 Ganita Prakash | Grade 7 | Part-II Complete the justification. Is an m × n grid tileable with 2 × 1 tiles, if both m and n are even? I...
Class VII Mathematics Ganita Prakash-II 6 sits on a black square of the grid, and each white square sits on a white square. If the plain grid is tileable, is the black-and-white-grid tileab...
Class VII Mathematics Ganita Prakash-II 6 animal shapes! Here are some examples. (a) (b) 161 Ganita Prakash | Grade 7 | Part-II (c) (d) Mathematicians are still exploring various ways of ti...
Class VII Mathematics Ganita Prakash-II 7 7 FINDING THE UNKNOWN 7.1 Find the Unknowns Unknown Weights Wehaveaweighingscalethatbehavesasfollows.Thenumbersrepresent same units of weight: Find...
Class VII Mathematics Ganita Prakash-II 7 the Unknown Figure it Out 1. Write 5 equations whose solution is x = – 2. 2. Find the value of each unknown: (a) 2y = 60 (b) – 8 = 5x – 3 (c) – 53w...
Class VII Mathematics Ganita Prakash-II 7 or, 2n + 1 = 99. Can you find ways to get the value of n, such that 2n + 1 = 99? Math Talk Is it possible to make a matchstick arrangement that app...
Class VII Mathematics Ganita Prakash-II 7 2y = 16. Solve the equations that you frame and check if you get the same value for the unknown weight as you got previously. Math Frame 5 equation...
Class VII Mathematics Ganita Prakash-II 7 RHS? For example, you can check by adding 10 to both sides. Since the LHS and the RHS of an equation have the same value, performing the same opera...
Class VII Mathematics Ganita Prakash-II 7 + 135 – 24 – (–67) = 7091. What is the value of the expression 12345 – 5432 + 135 – 24? 169 Ganita Prakash | Grade 7 | Part-II This problem also ca...
Class VII Mathematics Ganita Prakash-II 7 Ganita Prakash | Grade 7 | Part-II Subtracting 7 from both sides we get 2y + 7 – 7 = 21 – 7, which gives 2y = 14. We can directly find the value of...
Class VII Mathematics Ganita Prakash-II 7 these ways of solving an equation. 11y + (– 5) = 61 11y + (– 5) = 61 11y + (– 5) – (– 5) = 61 – (– 5). 11y = 61 – (– 5) 11y = 66 11y = 66 11y ÷ 11 ...