| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
and we remove the divisor, then the other side should be multiplied by this divisor for the equality to hold. For example, u 15 = 6 becomes u = 6 ×... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
+ 1 = 100. Find the value of k. Example 8: Madhubanti wants to organise a party. She decides to buy snacks for the party from the chaat shop in tow... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
80 feet. How many donkeys are there? How This many children are there? 189 Ganita Prakash | Grade 7 | Part-II SUMMARY • An algebraic equation is a ... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
= 18. Subtracting 5 from both sides, 25p = 500 – 50. f = 13. 25p = 450. Dividing both sides by 25, we get p = 450 ÷ 25 = 18. 18 people can be at he... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
+ 300 = 1000 a simpler equation if we 28 (x + 4) = 700. divide both sides by 4. 28x + 412 = 1000 Dividing both sides by 28 (x + 4) + 300 1000 Subtr... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
Think of a number. x Subtract 3 from the number. x – 3 Multiply the result by 4. 4 (x – 3) = 4x – 12 Add 8 to the product. 4x – 12 + 8 = 4x – 4 Sin... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
= 5. Share the equations you Math made with each other and discuss the methods used. Talk 179 Ganita Prakash | Grade 7 | Part-II Two such equations... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
+ 2 15w = 26 + 4w 12 15w = 30 x + 1 = – 8z = – 2 3 z = –2 w = 2 x + 1 = – 4 8 x = – 5 181 Ganita Prakash | Grade 7 | Part-II 7 8 9 4 (4q + 2) = 50 ... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
called Hisab al-jabr wal-muqabala, which means ‘calculation by restoring and balancing’. These ideas spread even further. By the 12th century, Al-K... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
+ (100) = 10x 400 + 6x = 10x 400 = 10x – 6x 400 = 4x 400 ÷ 4 = x 100 = x Therefore, the price of one horse = ₹ 100. 183 Ganita Prakash | Grade 7 | ... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
shapes, and situations. We express these generalisations using the language of algebra, which is both precise and powerful. Bījagaṇita also gives u... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
figure shows the diagram for a window with a grill. What is the gap between two rods in the grill? 3 cm 2 cm 34 cm 9. Inarestaurant,afruitjuicecost... |
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| Class VII |
Mathematics |
Ganita Prakash-II |
7 |
many sticks are needed to make the arrangement in position number 11 of the sequence? (c) Can an arrangement in this sequence be made using exactly... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
WORKING WITH FRACTIONS 8.1 Multiplication of Fractions Aaron walks 3 kilometres in 1 hour. How far can he walk in 5 hours? Thisisasimplequestion.We... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
again, we have — Distance covered = × 3 km. Distance in 1 hour Distance in 5hour Distance inhour Finding the product: 1. We can first find the dist... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
× = 5 × 2 = 10. It costs ₹10 for 1 hours of internet time. Figure it Out 1. Tenzin drinks 1 glass of milk every day. How many glasses of milk does ... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
Finding the product: 2 Distance covered in 1 hour =1 km. Therefore, the distance covered in1an hour is the length we get by 1 2 dividing into 2 equ... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
(ii) Now, we need to multiply2 by 3. Distance covered in3of an hour = 3 ×2 4 20 = . So,3 × 2= 6 = 3. 4 5 20 10 Discussion In the case of a fraction... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
unit. What is the area of this rectangle? We see that 8 such rectangles give the square of area 1 square unit. So, the area of each rectangle is1 s... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
4 3 3 1 4 3 (c) 5× 2 (d) 6× 5 Multiplying Numerators and Denominators Now, find 5 × 7. 12 18 Likethepreviouscase,letusfindtheproduct by performing ... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
common factor. In this case, we can divide them by 12. Reprint 2026-27 Working with Fractions 12 × 5 = 1 × 5= 5 . 7 × 24 7 × 2 14 Let us use the sa... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
of a rectangle of sid4ft and 95ft. 4. Tsewang plants four saplings in a row in his garden. The distance between two saplings is4 m. Find the distan... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
questions.] Situation Multiplication Relationship Situation 1 Both numbers are The product (16) is greater than 1 3 4 greater than both the (e.g.3 ... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
× ? = 12 Reprint 2026-27 Working with Fractions We can use this technique of converting division into multiplication problems to divide fractions. ... |
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| Class VII |
Mathematics |
Ganita Prakash |
8 |
get Dividend Divisor 5 2 10 the quotient is: = × = 1. First, find the number which gives 3 3 9 1 when multiplied by the divisor. Quotient We see th... |
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