Class name Subject Book title Chapter number Content Created at
Class XI Chemistry Chemistry Part-I 6 all behave as very weak bases due to K = 10 –4.75 = 1.77 × 10 M –5 their very small K b. Ammonia produces OH in – b NH + H O NH + + OH – aqueous so...
Class XI Chemistry Chemistry Part-I 6 so = 5.98 × 10 that if one is known, the other can be deduced. The concentration of the corresponding Considering the example of NH + and NH hydraz...
Class XI Chemistry Chemistry Part-I 6 a b 3 3 4 4 The ionization constant of NH , [OH ] / [NH ]} 3 3 K b = antilog (–pK ) i.eb = [H O ][OH ] = K 3 w = (5.6 ×10 –10) × (1.8 × 10 ) = 1.0 ...
Class XI Chemistry Chemistry Part-I 6 relation for conjugate acid-base pair, As the concentration of water remains constant it has been omitted from the K × K = K a b w denominator and ...
Class XI Chemistry Chemistry Part-I 6 200 chemistry K = {[H ][X ]} / [HX ] In general, when strength of H-A bond a2 decreases, that is, the energy required to break Here, Ka1nd K aa2 ca...
Class XI Chemistry Chemistry Part-I 6 a negatively charged increases. For example, 2 –3 HCO 3. Similarly, it is more difficult2–o remove Electronegativity of A increases a proton from a...
Class XI Chemistry Chemistry Part-I 6 × 10 = [OH ] – a shift in equilibrium on adding a substance that provides more of an ionic species already Therefore, [H ] = Kw/ [OH ] = 10 –14/ pr...
Class XI Chemistry Chemistry Part-I 6 – x) ≈ 0.05 The final 75 mL solution after neutralisation already contains Thus, 2.5 m mol NH ions (i.e. 0.033M), thus –5 4 + 1.8 × 10 = (x) (0.05 ...
Class XI Chemistry Chemistry Part-I 6 to reform corresponding acids/ NH Cl solution in water is less than 7. bases depending upon the nature of salts. Consider the hydrolysis of CH COON...
Class XI Chemistry Chemistry Part-I 6 of than 7, if the difference is negative. weak acid, CH COOH and strong base, NaOH 3 Problem 6.25 gets completely ionised in aqueous solution. CH C...
Class XI Chemistry Chemistry Part-I 6 This results in alkali are called Buffer Solutions. Buffer Reprint 2026-27 EQUILIBRIUM 203 solutions of known pH can be prepared from acid present ...
Class XI Chemistry Chemistry Part-I 6 saturated aqueous solution. (6.42) becomes: + 6.13.1 Solubility Product Constant pH= 9.25+ log [Conjugate acid,BH ] [Base,B] Let us now have a soli...
Class XI Chemistry Chemistry Part-I 6 The energy is released in the process of solvation. concentrations of the two ions will be equal to The amount of solvation enthalpy depends on the...
Class XI Chemistry Chemistry Part-I 6 x y with molar solubility S in equilibrium with Ksp of Some Common Ionic Salts at its saturated solution may be represented by 298K. the equation: ...
Class XI Chemistry Chemistry Part-I 6 salt is more soluble? Explain. Solution AgCN Ag + CN – Reprint 2026-27 206 chemistry K = [Ag ][CN ] = 6 × 10 –17 Dissolution of S mol/L of Ni(OH) p...
Class XI Chemistry Chemistry Part-I 6 1879 1884 1888 1892 1897 1901 0 1 1 2 2 3 3 3 4 .28 1905 1910 1914 1919 1923 1928 1932 1936 1941 1945 0 1 1 2 2 3 3 4 4 .29 1950 1954 1959 1963 196...
Class XI Chemistry Chemistry Part-I 6 the concentration of both the ions in turn increase the solubility of the salt so till once again K sp= Q spThis is applicable that K = Q . We have...
Class XI Chemistry Chemistry Part-I 6 = [S] [f S] = S {K /(K + [H ])} and is 2.0 × 10 . sp a a S = {K ([H ] + K )/K }1/2  (6.46) Solution sp a a Thus solubility S increases with increa...
Class XI Chemistry Chemistry Part-I 6 the equilibrium composition of a reaction mixture but increases the rate of chemical reaction by making available a new lower energy pathway for co...
Class XI Chemistry Chemistry Part-I 6 weak base undergo hydrolysis in aqueous solution. The definition of buffer solutions, and their importance are discussed briefly. The solubility eq...
Class XI Chemistry Chemistry Part-I 6 2661 2667 2673 2679 2685 1 1 2 2 3 4 4 5 6 .43 2692 2698 2704 2710 2716 2723 2729 2735 2742 2748 1 1 2 3 3 4 4 5 6 .44 2754 2761 2767 2773 2780 278...
Class XI Chemistry Chemistry Part-I 6 when equilibrium is restored finally and what will be the final vapour pressure? 6.2 What is K for the following equilibrium when the equilibrium c...
Class XI Chemistry Chemistry Part-I 6 mol of O is placed in a 10 L reaction vessel 2 2 –37 and allowed to form N 2O at a temperature for which K = 2.c × 10 , determine the composition o...
Class XI Chemistry Chemistry Part-I 6 according to the equation, H O (g) + CO (g) H (g) + CO (g) 2 2 2 Calculate the equilibrium constant for the reaction. 6.15 At 700 K, equilibrium co...
Class XI Chemistry Chemistry Part-I 6 after sometime. Has equilibrium been reached? 6.19 A sample of pure PCl 5 was introduced into an evacuated vessel at 473 K. After equilibrium was a...