Class name Subject Book title Chapter number Content Created at
Class XI Chemistry Chemistry Part-I 6 is governed by Henry’s temperature law, which states that the mass of a gas CO 2g) CO 2aq) [CO2(aq)]/[CO2(g)] is constant at a given dissolved in a...
Class XI Chemistry Chemistry Part II 1 +1 –2 0 0 2H O (l) 2H (g) + O (g) (7.26) Cr 2 (3) + 2 Al (s) Al2O 3s) + 2Cr(s) 2 2 2 (7 32) +1 –1 0 0 In each case, the reducing metal is a 2 aH (s...
Class XI Chemistry Chemistry Part II 1 Less active metals such as magnesium and 2 2 2 iron react with steam to produce dihydrogen gas: It is for this reason that the displacement reactio...
Class XI Chemistry Chemistry Part II 1 +1 –1 +2 –1 0 of identifying Br – and I in the laboratory Fe(s) + 2HCl(aq) → FeCl (aq) + H (g) 2 2 through the test popularly known as ‘Layer (7.39...
Class XI Chemistry Chemistry Part II 1 2 F2(g) + 2OH (aq) → 2 F (aq) + OF (2) + H O2l) 4. Disproportionation reactions (7.49) Disproportionation reactions are a special type (It is to be...
Class XI Accountancy Accountancy-II 1 the preparation of a balance sheet. 8.2.1 Expenditure Whenever payment and/or incurrence of an outlay are made for a purpose other than the settlem...
Class XI Chemistry Chemistry Part II 1 +7. The disproportionation reactions 0 –3 +1 for the other three oxoanions of chlorine – – are as follows: P4(s) + 3OH (aq)+ 3H O2l) → PH (g)3+ 3H ...
Class XI Chemistry Chemistry Part II 1 down 2 3 of lead nitrate into three components; (+5 state). Therefore reaction (d) is an example of disproportionation redox therefore, this is cat...
Class XI Chemistry Chemistry Part II 1 different from reality, is 2– 16/3. In the same fashion, in the species S4O 6 each of the two extreme sulphurs exhibits oxidation state of +5 and t...
Class XI Chemistry Chemistry Part II 1 undergo mixture of 2 mol of PbO and 1 mol of PbO . In PbO , lead is present in +4 change in oxidation number in the reaction 2 2 by assigning the o...
Class XI Chemistry Chemistry Part II 1 5 : Make the numbers of hydrogen between PbO and HNO 3as: atoms in the expression on the two sides 2PbO + 4HNO → 3Pb(NO ) + 2H3 2 2 equal by adding...
Class XI Chemistry Chemistry Part II 1 skeletal ionic equation is : Cr2O 7aq) + SO (a3) → Cr(aq)+SO (aq) 42– MnO (aq) + Br (aq) → MnO (s) + BrO (aq)– 4 2 3 This indicates that the dichro...
Class XI Chemistry Chemistry Part II 1 appropriate number of water + –2 + –2 +3 molecules (i.e. one H 2O molecule) on the Cr2O 72(aq) + 3SO 3–(aq) → 2Cr 3+ (aq) + left side to achieve ba...
Class XI Chemistry Chemistry Part II 1 (aq) → Fe (aq) (7.51) + –2 +3 balanced with respect to number of atoms 2– 3+ and the charges. Reduction half : Cr O2(a7) → Cr (aq) (7.52) For the r...
Class XI Chemistry Chemistry Part II 1 half reaction is thus +7 +4 rewritten to balance the charge: – Reduction half: MnO (aq)4→ MnO (s) 2 Fe 2+(aq) → Fe 3+ (aq) + e– (7.55) Step 3: To b...
Class XI Chemistry Chemistry Part II 1 2026-27 REDOX REACTIONS 249 (ii) If there is no dramatic auto-colour change the resultant equation is: – MnO – (aq) + 2H O (l)→ MnO (s) + 4 OH (aq)...
Class XI Chemistry Chemistry Part II 1 shows that I(aq) + 2 S O (aq)→2I (aq) + S O 2–(aq) (7.60) 2 2 3 4 6 the equation is balanced in respect of I , though insoluble in water, remains i...
Class XI Chemistry Chemistry Part II 1 (10– mol L ). This ensures a minimal The experiment corresponding to reaction ‘overshoot’incolourbeyondtheequivalence point, the point where the re...
Class XI Chemistry Chemistry Part II 1 The set-up as shown in Fig.7.3 forms of the same species are present. These is known as Daniell cell. When the switch is represent the species in t...
Class XI Chemistry Chemistry Part-I 6 chemistry Table 6.3 Expression Involving the The equilibrium constant for a general Equilibrium Concentration of reaction, Reactants a A + b B c C ...
Class XI Chemistry Chemistry Part II 1 the external circui(E)of hydrogen electrode is 0.00 volts. The to the cathode where these reduce the electrode potential value for each electrode ...
Class XI Chemistry Chemistry Part II 1 + 2H2O 1.23 – – Br 2+ 2e → 2Br 1.09 t NO –+ 4H + 3e – → NO(g) + 2H O t 0.97 e 3 2 e g 2Hg 2++ 2e – → Hg 22+ a 0.92 g + – g n Ag + e → Ag(s) i 0.80 ...
Class XI Chemistry Chemistry Part II 1 reactions form an important class of reactions in which oxidation and reduction occur simultaneously. Three tier conceptualisation viz, classical, ...
Class XI Chemistry Chemistry Part II 1 HF(g) + HOF(g) Justify that this reaction is a redox reaction. 2– 7.5 Calculate the oxidation number of sulphur, chromium and nitrogen in H 2SO 5 C...
Class XI Chemistry Chemistry Part II 1 agent is in excess. Justify this statement giving three illustrations. 7.12 How do you count for the following observations ? (a) Though alkaline p...