| Class XI |
Chemistry |
Chemistry Part II |
1 |
reaction occur ? – – + XeO 6 (aq) + 2F (aq) + 6H (aq) → XeO (g3+ F (g)2+ 3H O(l) 2 – What conclusion about the compound Na 4XeO (o6 which XeO 6 is ... |
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| Class XI |
Chemistry |
Chemistry Part II |
1 |
PH 3g) + HPO (a2) (b) N 2H 4l) + ClO3(aq) → NO(g) + Cl (g) (c) Cl O (g) + H O (aq) → ClO (aq) + O (g) + H + 2 7 2 2 2 2 7.20 What sorts of informat... |
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| Class XI |
Chemistry |
Chemistry Part II |
1 |
Fe 3(aq) and I (aq) (b) Ag +(aq) and Cu(s) 3+ (c) Fe (aq) and Cu(s) 3+ (d) Ag(s) and Fe (aq) (e) Br 2(aq) and Fe (aq). Reprint 2026-27 REDOX REACTI... |
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| Class XI |
Accountancy |
Financial Accounting-I |
6 |
A/c 4,500 (Furniture purchased for ` 5,000 wrongly debited to purchases account as ` 500, now rectified). (vi) Sales A/c Dr. 2,000 To Machinery 2,0... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
chemistry unit 8 Organic chemistry – sOme Basic PrinciPles and techniques I catenation a i t organic chemistry t 8.1 general intrOductiOn iupac o d... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
ch solution solution Problem 8.5 hoch ch ch ch ch ch ch ch Reprint 2026-27 chemistry molecular models m t c s p i t i s b c c c 8.3.2 three-dimensi... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
only carbon-carbon single bonds. 3 The IUPAC name for a homologous series of alkyl group is named by substituting ‘yl’ for such compounds is alkane... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
The branched butyl groups are called sec-butyl, isobutyl and tert-butyl group. carbon chains (branches) are called alkyl groups. For example: We al... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
of Organic compounds having Functional group(s) a p p Reprint 2026-27 chemistry i c ch oh ch oh ch oh ch ch oh ch choh – – h – oh t ch ch ch ch – –... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
e p n c h d e ch chch ch solution ch ch ch ch ch ch p i m ch ch c ch ch n d (ii) Position isomerism: 8.6 isOmerism t c h o s oh t ch ch ch oh ch... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
8.11 u i i ch –sch ch –cn ch –c π solution a nucleophile n nucleophilic a electrophile e electrophilic Problem 8.12 d g s C lCH C O,H N ,NO t solut... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
and ii. c–c t c c b t a resonance stabilisation energy c–c c c resonance energy t h r c–c c–c c c t t t i ii a t u Reprint 2026-27 chemistry Proble... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
i t 8.8.3 distillation t t i l t t c t t b Reprint 2026-27 chemistry theoretical plate. c o crude oil in petroleum industry. Distillation under red... |
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| Class XI |
Chemistry |
Chemistry Part-I |
6 |
equilibrium) is omitted from the concentration Equilibrium constant for the reverse terms. It is taken for granted that the reaction is the inverse... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
i c n s c t (A) Test for Nitrogen Fig.8.13 p p p p p t s p s ii Reprint 2026-27 organic chemistry – some basic principles and techniques t p s ii –... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
28×V V mLN a2STPweighs= 22400g 41.9mLof nitrogenweighs 28×41.9 g 28×V ×00 p 22400×m 28×41.9×100 Percentageof nitrogen 22400 0.3 Problem 8.21 =17.46... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
233 ×.157 1373K =42.10% c o ▯▯▯▯ co × a i o co → i co × b 8.10.5 Phosphorus o co a a co b a b i nh po m o a t m nh po l m p o m l ∴ 32×m 1 gO2 m n... |
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| Class XI |
Chemistry |
Chemistry Part II |
2 |
ch c cn oh + ch CH 3O → c h coch c ch ch b hs → ch ch sh b – ch c ch hci → ch cic – ch ch ch b ho → ch ch h o b– ch c– ch oh hb → ch cb ch ch ch h ... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
HYDROCARBONS 295 UNIT 9 HYDROCARBONS Hydrocarbons are the important sources of energy. After studying this unit, you will be able to name hydrocarb... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
manufacture mechanism; of polymers like polythene, polypropene, polystyrene etc. comprehend the structure of Higher hydrocarbons are used as solven... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
of such molecules of both types (open chain and close chain) keeping in mind that carbon is tetravalent and hydrogen is monovalent. For making mode... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
C 4 10… structures for C H . Four carbon atoms of H H H 4 10 C4H 10can be joined either in a continuous H—C—H replace any H 3yH—C—C—H or C H chain ... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
carbon atom as in methane or to formula but differ in their boiling points and only one carbon atom as in ethane is called other properties. Simila... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
grou s at different carbons of the chain. Solution – H n n 5 11 (i) CH 3– CH 2 CH – 2H – CH2– 2 CH –3CH – C2 – CH2– CH –2 2 H entan ol (ii) CH 3– C... |
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| Class XI |
Chemistry |
Chemistry Part II |
3 |
5 4 3 2 1 (b) CH –3CH – CH2– CH – C2 – C – CH – CH2 3 alphabetical arrangement (3,3-Diethyl-5-isopropyl-4-methyloctane) 1 2 3 4 5 6 7 8 9 10 sec is... |
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